1. How many protons, neutrons and electrons would be found in a23216 S ionA) 16 protons, 32 neutrons and 18 electronsB) 32 protons, 16 neutrons and 34 electronsC) 16 protons, 16 neutrons and 18 electronsD) 16 protons, 16 neutrons and 16 electronsE) 32 protons, 30 neutrons and 16 electrons
Question
- How many protons, neutrons and electrons would be found in a23216 S ionA) 16 protons, 32 neutrons and 18 electronsB) 32 protons, 16 neutrons and 34 electronsC) 16 protons, 16 neutrons and 18 electronsD) 16 protons, 16 neutrons and 16 electronsE) 32 protons, 30 neutrons and 16 electrons
Solution
The notation for the ion is written as follows: ²³²₁₆S⁻.
The superscript (232) is the atomic mass number, which is the sum of protons and neutrons. The subscript (16) is the atomic number, which represents the number of protons. The charge of the ion (-) indicates that it has gained electrons.
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The number of protons is given by the atomic number, which is 16. So, there are 16 protons.
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The number of neutrons is found by subtracting the atomic number from the atomic mass number. So, 232 - 16 = 216 neutrons.
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The number of electrons is found by adding the absolute value of the charge to the atomic number (since a negative charge means extra electrons). So, 16 + 1 = 17 electrons.
However, none of the options provided (A-E) match these numbers. There seems to be a mistake in the question or the options provided.
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