Find the sum of all the 4-digit numbers that can be formed from the digits 0, 1, 3, 4 and 5 without repetition of digits.

Sure, here is the step by step solution:

1. Since we are forming 4-digit numbers, the digit 0 cannot be at the thousand's place. So, the thousand's place can be filled in 4 ways (1, 3, 4, 5).

2. The hundred's place can be filled in 4 ways (0 and the remaining 3 digits not used in the thousand's place).

3. The ten's place can be filled in 3 ways (the remaining 3 digits).

4. The unit's place can be filled in 2 ways (the remaining 2 digits).

5. The sum of the digits at each place is 0+1+3+4+5 = 13.

6. So, the sum of all the 4-digit numbers is given by 443213*(1+10+100+1000) = 552,000.