To solve this problem, we need to understand that since we are using each digit once, we are essentially creating permutations of the digits 3, 5, 5, and 6.

Step 1: Determine the number of permutations. Since we have 4 digits, and one of them is repeated, the number of permutations is 4!/2! = 12.

Step 2: Calculate the sum of the digits in each place. For each permutation, each digit will appear in each place (thousands, hundreds, tens, ones) 3 times (since there are 12 permutations and each digit will appear in each place equally). So, the sum of the digits in each place is 3*(3+5+5+6) = 57.

Step 3: Calculate the total sum. Since the sum of the digits in each place is 57, the total sum of all the numbers is 57*(1000+100+10+1) = 64440.

However, none of the choices match this result. There might be a mistake in the problem or the choices.

Question

To solve this problem, we need to understand that since we are using each digit once, we are essentially creating permutations of the digits 3, 5, 5, and 6.

Step 1: Determine the number of permutations. Since we have 4 digits, and one of them is repeated, the number of permutations is 4!/2! = 12.

Step 2: Calculate the sum of the digits in each place. For each permutation, each digit will appear in each place (thousands, hundreds, tens, ones) 3 times (since there are 12 permutations and each digit will appear in each place equally). So, the sum of the digits in each place is 3*(3+5+5+6) = 57.

Step 3: Calculate the total sum. Since the sum of the digits in each place is 57, the total sum of all the numbers is 57*(1000+100+10+1) = 64440.

However, none of the choices match this result. There might be a mistake in the problem or the choices.

Knowee AI · Accepted Answer

To solve this problem, we need to understand that since we are using each digit once, we are essentially creating permutations of the digits 3, 5, 5, and 6.

Step 1: Determine the number of permutations. Since we have 4 digits, and one of them is repeated, the number of permutations is 4!/2! = 12.

Step 2: Calculate the sum of the digits in each place. For each permutation, each digit will appear in each place (thousands, hundreds, tens, ones) 3 times (since there are 12 permutations and each digit will appear in each place equally). So, the sum of the digits in each place is 3*(3+5+5+6) = 57.

Step 3: Calculate the total sum. Since the sum of the digits in each place is 57, the total sum of all the numbers is 57*(1000+100+10+1) = 64440.

However, none of the choices match this result. There might be a mistake in the problem or the choices.

The sum of all the possible numbers of 4 digits formed by digits 3, 5, 5, and 6 using each digit once isChoices:- 64427 63327 65297 43521

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