what wiil be the output of the following pseudo code?Integer a,b,cSet a=2,b=7, c=9if(9>c || (b&a)<a) c=(b+1)+bElse a=a+c b=5^bEnd ifPrint a+b+c
Question
what wiil be the output of the following pseudo code?Integer a,b,cSet a=2,b=7, c=9if(9>c || (b&a)<a) c=(b+1)+bElse a=a+c b=5^bEnd ifPrint a+b+c
Solution
The pseudo code provided can be broken down as follows:
- Initialize variables a, b, c with values 2, 7, 9 respectively.
- Check the condition in the if statement: 9 > c OR (b & a) < a. Here, '&' is a bitwise AND operation. The condition becomes: 9 > 9 OR (7 & 2) < 2, which simplifies to false OR 2 < 2, which is false. So, the condition in the if statement is false.
- Since the if condition is false, the program will execute the else block. In the else block, a is updated to a + c, which is 2 + 9 = 11. And b is updated to 5 XOR b, which is 5 XOR 7 = 2. Here, '^' is a bitwise XOR operation.
- Finally, the program prints the sum of a, b, and c, which is 11 + 2 + 9 = 22.
So, the output of the pseudo code will be 22.
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