An electric field E = i - 3k oscillates with a magnetic field H = 2i - 5j producing an electromagnetic wave (light), where i, j and k are unit vectors in the x, y and z directions respectively. Determine the poynting vector, S.*1 point-i - 3k-4i – 5j-15i - 6j - 5k15i + 3j - 20k
Question
An electric field E = i - 3k oscillates with a magnetic field H = 2i - 5j producing an electromagnetic wave (light), where i, j and k are unit vectors in the x, y and z directions respectively. Determine the poynting vector, S.*1 point-i - 3k-4i – 5j-15i - 6j - 5k15i + 3j - 20k
Solution 1
The Poynting vector S is given by the cross product of the electric field E and the magnetic field H. In vector notation, this is written as S = E × H.
Given E = i - 3k and H = 2i - 5j, we can calculate the cross product as follows:
S = E × H = (i - 3k) × (2i - 5j) = i × 2i - i × 5j - 3k × 2i + 3k × 5j = 0i - 5k - 6j - 15i = -15i - 6j - 5k
So, the Poynting vector S is -15i - 6j - 5k.
Solution 2
The Poynting vector S is given by the cross product of the electric field E and the magnetic field H. In vector notation, this is written as S = E x H.
Given E = i - 3k and H = 2i - 5j, we can calculate the cross product as follows:
S = E x H = (i - 3k) x (2i - 5j) = i x 2i - i x 5j - 3k x 2i + 3k x 5j = 0i - 5k - 6j - 15i = -15i - 6j - 5k
So, the Poynting vector S is -15i - 6j - 5k.
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