A half wave rectifier has a 200V rms. source and thestep-down transformerhas a turns ratioof41.What will be the peak voltage across the load ignoring the drop across the diodeChoose the best optionClear Response70.7V40V30V50V
Question
A half wave rectifier has a 200V rms. source and thestep-down transformerhas a turns ratioof41.What will be the peak voltage across the load ignoring the drop across the diodeChoose the best optionClear Response70.7V40V30V50V
Solution
The peak voltage across the load can be calculated using the formula:
Vpeak = Vrms * sqrt(2)
Where: Vrms is the root mean square voltage, and sqrt(2) is the square root of 2.
Given that the Vrms is 200V and the turns ratio of the transformer is 4:1, the Vrms across the secondary of the transformer is:
Vrms_secondary = Vrms_primary / turns ratio Vrms_secondary = 200V / 4 Vrms_secondary = 50V
Now, we can calculate the peak voltage:
Vpeak = Vrms_secondary * sqrt(2) Vpeak = 50V * sqrt(2) Vpeak = 70.7V
So, the peak voltage across the load, ignoring the drop across the diode, is 70.7V. Therefore, the best option is 70.7V.
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