A half wave rectifier uses capacitor of 680 µF in parallel withload resistance of 200 Ω. If the average output voltage is 28 V.Calculate peak-to-peak voltage, AC voltage present at the output,and ripple facto
Question
A half wave rectifier uses capacitor of 680 µF in parallel withload resistance of 200 Ω. If the average output voltage is 28 V.Calculate peak-to-peak voltage, AC voltage present at the output,and ripple facto
Solution 1
To calculate the peak-to-peak voltage, we need to find the difference between the maximum and minimum values of the output voltage. In a half wave rectifier, the minimum value is 0 V, so we only need to find the maximum value.
The average output voltage is given as 28 V. Since the output voltage is a sinusoidal waveform, the peak value can be found by multiplying the average voltage by the square root of 2 (approximately 1.414).
Peak voltage = Average voltage x √2 Peak voltage = 28 V x 1.414 Peak voltage ≈ 39.6 V
The peak-to-peak voltage is then twice the peak voltage.
Peak-to-peak voltage = 2 x Peak voltage Peak-to-peak voltage = 2 x 39.6 V Peak-to-peak voltage ≈ 79.2 V
To find the AC voltage present at the output, we need to subtract the DC component (average voltage) from the peak-to-peak voltage.
AC voltage = Peak-to-peak voltage - Average voltage AC voltage = 79.2 V - 28 V AC voltage ≈ 51.2 V
Finally, to calculate the ripple factor, we need to divide the AC voltage by the average voltage.
Ripple factor = AC voltage / Average voltage Ripple factor = 51.2 V / 28 V Ripple factor ≈ 1.83
Solution 2
To calculate the peak-to-peak voltage, we need to find the difference between the maximum and minimum values of the output voltage. In a half wave rectifier, the maximum value of the output voltage is equal to the average output voltage.
Given that the average output voltage is 28 V, the peak-to-peak voltage is also 28 V.
To calculate the AC voltage present at the output, we need to subtract the DC component (average output voltage) from the peak-to-peak voltage. In this case, the AC voltage is 0 V since the peak-to-peak voltage is equal to the average output voltage.
The ripple factor is a measure of the amount of AC voltage present in the output compared to the DC voltage. It is calculated by dividing the root mean square (RMS) value of the AC voltage by the average output voltage.
Since the AC voltage is 0 V in this case, the ripple factor is also 0.
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