Consider the following code. Assume that copy has been imported.w = [1, 2]z = copy.copy(w)z = copy.deepcopy(w)print(z + w)z = wwhy there are 8 different objects will exist in the computer’s memory after the code has been executed?Assume that no optimizations have been performed and that garbage collection has not been executed.
Question
Consider the following code. Assume that copy has been imported.w = [1, 2]z = copy.copy(w)z = copy.deepcopy(w)print(z + w)z = wwhy there are 8 different objects will exist in the computer’s memory after the code has been executed?Assume that no optimizations have been performed and that garbage collection has not been executed.
Solution
The eight different objects in memory after the code execution are as follows:
- The list object [1, 2] initially assigned to variable 'w'.
- The variable 'w' itself, which is a reference to the list object [1, 2].
- The copy of the list object [1, 2] created by copy.copy(w) and initially assigned to 'z'.
- The variable 'z' itself, which is a reference to the copied list object.
- The deepcopy of the list object [1, 2] created by copy.deepcopy(w) and assigned to 'z'.
- The list object resulting from the operation z + w, which is printed but not assigned to a variable.
- The integer object '1' in the list.
- The integer object '2' in the list.
Note: The integer objects '1' and '2' are counted as separate objects because they are part of the list object and are stored separately in memory.
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