An alloy of iron and nickil weight 50g. It contains 80% iron. How much iron should be added to thealloy so that percentage of iron is increased to 90?(A) 50 g (B) 60 g (C) 30 g (D) 40 g
Question
An alloy of iron and nickil weight 50g. It contains 80% iron. How much iron should be added to thealloy so that percentage of iron is increased to 90?(A) 50 g (B) 60 g (C) 30 g (D) 40 g
Solution
The problem can be solved in the following steps:
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First, we need to find out how much iron is currently in the alloy. Since the alloy is 80% iron and weighs 50g, the amount of iron in the alloy is 80/100 * 50 = 40g.
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The alloy also contains nickel, which weighs 50g - 40g = 10g.
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We want the final alloy to be 90% iron. Let's denote the amount of iron that needs to be added as x. The total weight of the new alloy will be 50g (original weight) + x (added iron).
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According to the problem, the weight of the iron (40g + x) should be 90% of the total weight of the new alloy. So, we can set up the equation: (40g + x) = 90/100 * (50g + x).
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Solving this equation for x gives us x = 50g.
So, we need to add 50g of iron to the alloy to increase the percentage of iron to 90%. Therefore, the answer is (A) 50 g.
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