The distance (d) from a point to a line given the equation of the line Ax + By + C = 0 and the point (x0, y0) is given by the formula:

d = |Ax0 + By0 + C| / sqrt(A^2 + B^2)

In this case, the line is 3x + 4y + 1 = 0 and the point is (5, 3). So, A = 3, B = 4, C = 1, x0 = 5, and y0 = 3.

Substitute these values into the formula:

d = |3*5 + 4*3 + 1| / sqrt(3^2 + 4^2)
d = |15 + 12 + 1| / sqrt(9 + 16)
d = |28| / sqrt(25)
d = 28 / 5
d = 5.6 units

So, the distance of the point (5, 3) from the line 3x + 4y + 1 = 0 is 5.6 units.

Question

The distance (d) from a point to a line given the equation of the line Ax + By + C = 0 and the point (x0, y0) is given by the formula:

d = |Ax0 + By0 + C| / sqrt(A^2 + B^2)

In this case, the line is 3x + 4y + 1 = 0 and the point is (5, 3). So, A = 3, B = 4, C = 1, x0 = 5, and y0 = 3.

Substitute these values into the formula:

d = |3*5 + 4*3 + 1| / sqrt(3^2 + 4^2)
d = |15 + 12 + 1| / sqrt(9 + 16)
d = |28| / sqrt(25)
d = 28 / 5
d = 5.6 units

So, the distance of the point (5, 3) from the line 3x + 4y + 1 = 0 is 5.6 units.

Knowee AI · Accepted Answer

The distance (d) from a point to a line given the equation of the line Ax + By + C = 0 and the point (x0, y0) is given by the formula:

d = |Ax0 + By0 + C| / sqrt(A^2 + B^2)

In this case, the line is 3x + 4y + 1 = 0 and the point is (5, 3). So, A = 3, B = 4, C = 1, x0 = 5, and y0 = 3.

Substitute these values into the formula:

d = |3*5 + 4*3 + 1| / sqrt(3^2 + 4^2)
d = |15 + 12 + 1| / sqrt(9 + 16)
d = |28| / sqrt(25)
d = 28 / 5
d = 5.6 units

So, the distance of the point (5, 3) from the line 3x + 4y + 1 = 0 is 5.6 units.

The distance of point (5, 3) from the line 3x + 4y + 1 = 0 is