The distance of (3, 0) from 3x-4y+6=0A.1B.2C.3D.4

To find the distance between a point and a line, we can use the formula:

Distance = |Ax + By + C| / √(A^2 + B^2)

In this case, the equation of the line is 3x - 4y + 6 = 0. Comparing this equation with the standard form Ax + By + C = 0, we have A = 3, B = -4, and C = 6.

The point given is (3, 0), which means x = 3 and y = 0.

Substituting these values into the formula, we get:

Distance = |3(3) - 4(0) + 6| / √(3^2 + (-4)^2) = |9 + 6| / √(9 + 16) = |15| / √25 = 15 / 5 = 3

Therefore, the distance of the point (3, 0) from the line 3x - 4y + 6 = 0 is 3.

Hence, the correct answer is C. 3.