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Solve the following quadratic equation for all values of xx in simplest form.3, left parenthesis, x, squared, minus, 2, right parenthesis, minus, 1, equals, 53(x 2 −2)−1=5AnswerAttempt 1 out of 2

Question

Solve the following quadratic equation for all values of xx in simplest form.3, left parenthesis, x, squared, minus, 2, right parenthesis, minus, 1, equals, 53(x 2 −2)−1=5AnswerAttempt 1 out of 2

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Solution

Claro, vamos a resolver la ecuación cuadrática paso a paso.

La ecuación dada es: 3(x22)1=5 3(x^2 - 2) - 1 = 5

Paso 1: Simplificar la ecuación. 3(x22)1=5 3(x^2 - 2) - 1 = 5 Distribuimos el 3 dentro del paréntesis: 3x261=5 3x^2 - 6 - 1 = 5 Simplificamos los términos constantes: 3x27=5 3x^2 - 7 = 5

Paso 2: Aislar el término cuadrático. Sumamos 7 a ambos lados de la ecuación: 3x27+7=5+7 3x^2 - 7 + 7 = 5 + 7 3x2=12 3x^2 = 12

Paso 3: Resolver para x2 x^2 . Dividimos ambos lados de la ecuación por 3: x2=123 x^2 = \frac{12}{3} x2=4 x^2 = 4

Paso 4: Encontrar los valores de x x . Tomamos la raíz cuadrada de ambos lados de la ecuación: x=±4 x = \pm \sqrt{4} x=±2 x = \pm 2

Por lo tanto, las soluciones de la ecuación cuadrática son: x=2 x = 2 x=2 x = -2

This problem has been solved

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