An organic chemistry student prepared 799. mL of a DMSO-water solution at 15.0 °C by measuring out 494. mL of DMSO and 313. mL of water and mixing them.Calculate the volume percent of DMSO in this solution.Be sure your answer has the right number of significant digits.
Question
An organic chemistry student prepared 799. mL of a DMSO-water solution at 15.0 °C by measuring out 494. mL of DMSO and 313. mL of water and mixing them.Calculate the volume percent of DMSO in this solution.Be sure your answer has the right number of significant digits.
Solution
The volume percent of a solution is calculated using the formula:
Volume percent = (volume of solute / volume of solution) * 100%
In this case, DMSO is the solute and the total solution is the sum of the volumes of DMSO and water.
Step 1: Calculate the total volume of the solution Total volume = volume of DMSO + volume of water Total volume = 494 mL + 313 mL = 807 mL
Step 2: Calculate the volume percent of DMSO Volume percent of DMSO = (volume of DMSO / total volume) * 100% Volume percent of DMSO = (494 mL / 807 mL) * 100% = 61.2%
So, the volume percent of DMSO in the solution is 61.2%. This answer has three significant digits, which is appropriate given the number of significant digits in the original measurements.
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