A chemist prepares a mixture of acetone and water at a temperature of 18.0 °C. He measures out 40.1 mL of acetone and mixes it with 303. mL of water. He measures the volume of the solution after it is well mixed and finds that it is 329. mL. The density of acetone is 0.78 /gmL and the density of water is 1.0 /gmL.Calculate the volume percent of acetone in this solution.Be sure your answer has the right number of significant digits.
Question
A chemist prepares a mixture of acetone and water at a temperature of 18.0 °C. He measures out 40.1 mL of acetone and mixes it with 303. mL of water. He measures the volume of the solution after it is well mixed and finds that it is 329. mL. The density of acetone is 0.78 /gmL and the density of water is 1.0 /gmL.Calculate the volume percent of acetone in this solution.Be sure your answer has the right number of significant digits.
Solution
To calculate the volume percent of acetone in the solution, we first need to know the total volume of the solution and the volume of the acetone.
The total volume of the solution is given as 329 mL.
The volume of the acetone is given as 40.1 mL.
The volume percent is calculated by dividing the volume of the acetone by the total volume of the solution and then multiplying by 100 to get a percentage.
So, the calculation would be:
(40.1 mL / 329 mL) * 100 = 12.2 %
Therefore, the volume percent of acetone in the solution is 12.2%. This answer has the correct number of significant digits.
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