Solve the equation 3, x, squared, minus, 20, x, plus, 34, equals, 83x 2 −20x+34=8 to the nearest tenth.

The given equation seems to be a bit unclear, but I'll assume you're asking to solve the quadratic equation 3x^2 - 20x + 34 = 8.

Step 1: Rearrange the equation to set it equal to zero.

3x^2 - 20x + 34 - 8 = 0

This simplifies to:

3x^2 - 20x + 26 = 0

Step 2: Use the quadratic formula to solve for x. The quadratic formula is x = [-b ± sqrt(b^2 - 4ac)] / (2a), where a, b, and c are the coefficients from the quadratic equation ax^2 + bx + c.

In this equation, a = 3, b = -20, and c = 26.

Step 3: Substitute a, b, and c into the quadratic formula and solve for x.

x = [20 ± sqrt((-20)^2 - 4326)] / (2*3) x = [20 ± sqrt(400 - 312)] / 6 x = [20 ± sqrt(88)] / 6 x = [20 ± 9.38] / 6

Step 4: Solve for the two possible values of x.

x = (20 + 9.38) / 6 = 4.9 (to the nearest tenth) x = (20 - 9.38) / 6 = 1.8 (to the nearest tenth)

So, the solutions to the equation 3x^2 - 20x + 26 = 0 are x = 4.9 and x = 1.8 (to the nearest tenth).