Abbey is doing the long jump at her school's athletics day. Her initial velocity is 2.0 m/s2.0 m/s and she accelerates for 8.0 s8.0 s. Her velocity is 7.0 m/s7.0 m/s when she jumps. Calculate Abbey's acceleration: 𝑎=𝑣−𝑢Δ𝑡a= Δtv−u Make sure to include appropriate units in your answer. Round your answer to two significant figures.
Question
Abbey is doing the long jump at her school's athletics day. Her initial velocity is 2.0 m/s2.0 m/s and she accelerates for 8.0 s8.0 s. Her velocity is 7.0 m/s7.0 m/s when she jumps. Calculate Abbey's acceleration: 𝑎=𝑣−𝑢Δ𝑡a= Δtv−u Make sure to include appropriate units in your answer. Round your answer to two significant figures.
Solution
To calculate Abbey's acceleration, we will use the formula a = (v - u) / Δt.
Here, v = final velocity = 7.0 m/s u = initial velocity = 2.0 m/s Δt = time = 8.0 s
Substituting these values into the formula, we get:
a = (7.0 m/s - 2.0 m/s) / 8.0 s = 5.0 m/s / 8.0 s = 0.625 m/s²
So, Abbey's acceleration is 0.625 m/s². However, the question asks for the answer to be rounded to two significant figures. Therefore, the final answer is 0.63 m/s².
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