Hannah is cycling down a hill. Her velocity increases by 1 m/s1 m/s in 3 s3 s. Calculate Hannah's acceleration: 𝑎=Δ𝑣Δ𝑡a= ΔtΔv
Question
Hannah is cycling down a hill. Her velocity increases by 1 m/s1 m/s in 3 s3 s. Calculate Hannah's acceleration: 𝑎=Δ𝑣Δ𝑡a= ΔtΔv
Solution
The formula for acceleration is a = Δv/Δt.
In this case, Hannah's velocity (v) increases by 1 m/s over a time (t) of 3 seconds.
So, Δv = 1 m/s and Δt = 3 s.
Substitute these values into the formula:
a = Δv/Δt = 1 m/s / 3 s = 0.33 m/s².
So, Hannah's acceleration is 0.33 m/s².
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