37. What change in volume results if 60mL of a gas is cooled from 33 degree Celsius to 5.0 degree Celsius?*1 point54.5 mL32.5 mL12.5 mL5.5 mL

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, assuming pressure is constant. The formula for Charles's Law is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Step 1: Convert the temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = C + 273.15.

T1 = 33°C = 33 + 273.15 = 306.15 K T2 = 5°C = 5 + 273.15 = 278.15 K

Step 2: Substitute the known values into Charles's Law and solve for V2.

V1/T1 = V2/T2 60 mL / 306.15 K = V2 / 278.15 K V2 = (60 mL * 278.15 K) / 306.15 K V2 = 54.5 mL

So, the volume of the gas at 5.0 degree Celsius is 54.5 mL. The change in volume is the final volume minus the initial volume: 54.5 mL - 60 mL = -5.5 mL. The negative sign indicates a decrease in volume. So, the volume decreases by 5.5 mL.