This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant.

Boyle's Law formula is P1*V1 = P2*V2.

Here, P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Given in the problem:
P1 = 3 atm
V1 = 2.0 L
P2 = 0.5 atm
V2 = ?

We can substitute these values into the formula:

3 atm * 2.0 L = 0.5 atm * V2

Solving for V2 gives:

V2 = (3 atm * 2.0 L) / 0.5 atm = 12 L

So, the volume of the balloon would be 12 L.

Question

This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant.

Boyle's Law formula is P1*V1 = P2*V2.

Here, P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Given in the problem:
P1 = 3 atm
V1 = 2.0 L
P2 = 0.5 atm
V2 = ?

We can substitute these values into the formula:

3 atm * 2.0 L = 0.5 atm * V2

Solving for V2 gives:

V2 = (3 atm * 2.0 L) / 0.5 atm = 12 L

So, the volume of the balloon would be 12 L.

Knowee AI · Accepted Answer

This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant.

Boyle's Law formula is P1*V1 = P2*V2.

Here, P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Given in the problem:
P1 = 3 atm
V1 = 2.0 L
P2 = 0.5 atm
V2 = ?

We can substitute these values into the formula:

3 atm * 2.0 L = 0.5 atm * V2

Solving for V2 gives:

V2 = (3 atm * 2.0 L) / 0.5 atm = 12 L

So, the volume of the balloon would be 12 L.

36. A balloon with a volume of 2.0 L is filled with a gas at 3 atm. If the pressure is reduced to 0.5 atm without change in temperature, what would be the volume of the balloon?*1 point3.0 L6.0 L12 L24 L

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