A vessel contains 5 litres of wine. 3 litres are drawn from it and replaced with 3 litres of water. This operation is repeated 1 more times. How many litres of wine is left?
Question
A vessel contains 5 litres of wine. 3 litres are drawn from it and replaced with 3 litres of water. This operation is repeated 1 more times. How many litres of wine is left?
Solution
Sure, here is the step by step solution:
- Initially, the vessel contains 5 litres of wine.
- When 3 litres are drawn out, the amount of wine left in the vessel is 5 - 3 = 2 litres.
- Then 3 litres of water is added, making the total volume in the vessel back to 5 litres. But now, it's a mixture of 2 litres of wine and 3 litres of water.
- The ratio of wine to the total volume is now 2/5.
- When the operation is repeated, again 3 litres of the mixture is drawn out. This means 3 * (2/5) = 1.2 litres of wine is drawn out, and 1.8 litres of water is drawn out.
- So, the amount of wine left in the vessel after the second operation is 2 - 1.2 = 0.8 litres.
So, there are 0.8 litres of wine left in the vessel after the operation is repeated once more.
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