A block of iron of mass 7.5 kg and of dimensions 12 cm x 8 cm x 10 cm is kept on a table top on it's base of side 12 cm x 8 cm. Calculate (a) thrust and (b) pressure exerted on the table top. Take 1 kgf = 10 N. A 60N, 20 Pa B 75N, 0.2 Pa
Question
A block of iron of mass 7.5 kg and of dimensions 12 cm x 8 cm x 10 cm is kept on a table top on it's base of side 12 cm x 8 cm. Calculate (a) thrust and (b) pressure exerted on the table top. Take 1 kgf = 10 N. A 60N, 20 Pa B 75N, 0.2 Pa
Solution
To solve this problem, we need to understand the concepts of thrust, pressure, and the relationship between mass and weight.
(a) Thrust (or weight) is the force exerted by an object due to gravity. It can be calculated using the formula:
Thrust = mass x gravity
Given that the mass of the iron block is 7.5 kg and gravity is approximated as 10 N/kg (since 1 kgf = 10 N), we can substitute these values into the formula:
Thrust = 7.5 kg x 10 N/kg = 75 N
So, the thrust exerted by the block on the table top is 75 N.
(b) Pressure is the amount of force exerted per unit area. It can be calculated using the formula:
Pressure = Force / Area
The force in this case is the thrust we calculated earlier, which is 75 N. The area is the area of the base of the block that is in contact with the table top. Given that the dimensions of this base are 12 cm x 8 cm, we can calculate the area in square meters (since the unit of pressure is N/m² or Pa):
Area = 12 cm x 8 cm = 96 cm² = 96 x 10^-4 m² = 0.0096 m²
Substituting these values into the formula gives:
Pressure = 75 N / 0.0096 m² = 7812.5 Pa
So, the pressure exerted by the block on the table top is 7812.5 Pa.
Therefore, the correct answer is neither A nor B. The correct values are 75N for the thrust and 7812.5 Pa for the pressure.
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