A block of wood of mass 10 kg is placed on a tabletop. The dimensions of the block are 40 cm X 30 cmX 10 cm. If the block lies on the tabletop with sides of dimension 40cm X 20cm, calculate the pressureexerted
Question
A block of wood of mass 10 kg is placed on a tabletop. The dimensions of the block are 40 cm X 30 cmX 10 cm. If the block lies on the tabletop with sides of dimension 40cm X 20cm, calculate the pressureexerted
Solution
To calculate the pressure exerted by the block of wood on the tabletop, we need to use the formula for pressure:
Pressure = Force / Area
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First, we need to calculate the force. The force exerted by the block on the table is its weight, which is the mass times the acceleration due to gravity. Assuming the acceleration due to gravity is 9.8 m/s², the force is:
Force = mass x gravity Force = 10 kg x 9.8 m/s² = 98 Newtons
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Next, we need to calculate the area over which this force is distributed. The block is lying on the tabletop with sides of dimension 40 cm x 30 cm. We need to convert these dimensions to meters (since the standard unit of measurement in physics is meters), so:
40 cm = 0.4 m 30 cm = 0.3 m
Area = length x width Area = 0.4 m x 0.3 m = 0.12 m²
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Finally, we can calculate the pressure:
Pressure = Force / Area Pressure = 98 N / 0.12 m² = 816.67 Pascal
So, the pressure exerted by the block of wood on the tabletop is approximately 816.67 Pascal.
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