This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant.

Boyle's Law is represented by the formula P1V1 = P2V2, where:

- P1 is the initial pressure
- V1 is the initial volume
- P2 is the final pressure
- V2 is the final volume

Given in the problem:

- P1 = 150 kPa
- V1 = 275 mL
- P2 = 260 kPa
- V2 = ?

We can substitute the given values into the formula and solve for V2:

150 kPa * 275 mL = 260 kPa * V2

Rearranging the equation to solve for V2 gives:

V2 = (150 kPa * 275 mL) / 260 kPa

Calculating the above expression gives:

V2 ≈ 158.65 mL

So, the new volume of the argon sample when the pressure is changed from 150 kPa to 260 kPa is approximately 158.65 mL.

Question

This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant.

Boyle's Law is represented by the formula P1V1 = P2V2, where:

- P1 is the initial pressure
- V1 is the initial volume
- P2 is the final pressure
- V2 is the final volume

Given in the problem:

- P1 = 150 kPa
- V1 = 275 mL
- P2 = 260 kPa
- V2 = ?

We can substitute the given values into the formula and solve for V2:

150 kPa * 275 mL = 260 kPa * V2

Rearranging the equation to solve for V2 gives:

V2 = (150 kPa * 275 mL) / 260 kPa

Calculating the above expression gives:

V2 ≈ 158.65 mL

So, the new volume of the argon sample when the pressure is changed from 150 kPa to 260 kPa is approximately 158.65 mL.

Knowee AI · Accepted Answer