If a gas had an initial volume of 35 L at a pressure of 1.5 atm, then what would be the new volume if the pressure was changed to 100 kPa. Question 9 options:
Question
If a gas had an initial volume of 35 L at a pressure of 1.5 atm, then what would be the new volume if the pressure was changed to 100 kPa.
Question 9 options:
Solution
To solve this problem, we can use the ideal gas law, which states that the product of the initial pressure and volume is equal to the product of the final pressure and volume. This can be written as:
P1V1 = P2V2
Where: P1 = initial pressure V1 = initial volume P2 = final pressure V2 = final volume
We are given: P1 = 1.5 atm V1 = 35 L P2 = 100 kPa
However, the pressures are not in the same units. We need to convert either atm to kPa or kPa to atm. The conversion factor is 1 atm = 101.325 kPa. So, let's convert 1.5 atm to kPa:
P1 = 1.5 atm * 101.325 kPa/atm = 151.9875 kPa
Now we can substitute P1, V1, and P2 into the equation and solve for V2:
151.9875 kPa * 35 L = 100 kPa * V2 V2 = (151.9875 kPa * 35 L) / 100 kPa
Calculate the above expression to find the value of V2.
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