Find the value of 'a' if two vector A = 2i + aj +K & B = 4i - 3j + 2k are perpendicular to eachotherA. 20B. 15C. 10D. 5
Question
Find the value of 'a' if two vector A = 2i + aj +K & B = 4i - 3j + 2k are perpendicular to eachotherA. 20B. 15C. 10D. 5
Solution
Two vectors are perpendicular to each other if their dot product is zero. The dot product of two vectors A = ai + bj + ck and B = di + ej + fk is given by:
A.B = ad + be + cf
Given vectors A = 2i + aj + k and B = 4i - 3j + 2k, their dot product is:
A.B = (24) + (a-3) + (1*2) = 0
Solving this equation will give us the value of 'a':
8 - 3a + 2 = 0 -3a = -10 a = 10/3
So, none of the options A, B, C, D are correct. The value of 'a' is 10/3.
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