What is the output after this code is compiled and its executable run?#include <iostream>using namespace std;void pn( int x, int& p, int& n ){ p = x-1; n = x+1;}int main(){ int x = 10, y, z; pn( x, y, z ); cout << y << ", " << z << "\n"; return 0;}Select one:a.9, 10b.9, 11c.10, 11d.11, 9
Question
What is the output after this code is compiled and its executable run?#include <iostream>using namespace std;void pn( int x, int& p, int& n ){ p = x-1; n = x+1;}int main(){ int x = 10, y, z; pn( x, y, z ); cout << y << ", " << z << "\n"; return 0;}Select one:a.9, 10b.9, 11c.10, 11d.11, 9
Solution
The output of the code will be 9, 11. So, the correct answer is b. 9, 11.
Here's the step by step explanation:
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The code starts with the inclusion of the iostream library which allows the program to perform input and output operations.
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The 'using namespace std' line allows the program to use names for objects and variables from the standard library.
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A function 'pn' is declared which takes three parameters: an integer 'x' and two references to integers 'p' and 'n'. Inside this function, 'p' is assigned the value of 'x-1' and 'n' is assigned the value of 'x+1'.
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The 'main' function is where the program starts execution. An integer 'x' is declared and initialized with the value 10. Two more integers 'y' and 'z' are declared.
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The function 'pn' is called with 'x', 'y', and 'z' as arguments. This will assign 'y' the value of 'x-1' (which is 9) and 'z' the value of 'x+1' (which is 11).
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The values of 'y' and 'z' are then printed to the console, separated by a comma. So, the output will be "9, 11".
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The program then returns 0, indicating successful execution.
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