A container with a moveable piston contains 2.35 L of helium at a pressure of 1.25 atm. What will the new pressure be if the volume is increased to 3.50 L?Multiple choice question.1.03 atm15.5 atm1.86 atm0.839 atm
Question
A container with a moveable piston contains 2.35 L of helium at a pressure of 1.25 atm. What will the new pressure be if the volume is increased to 3.50 L?Multiple choice question.1.03 atm15.5 atm1.86 atm0.839 atm
Solution
This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In other words, P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Here's how to solve it:
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Identify the initial pressure (P1), initial volume (V1), and final volume (V2). In this case, P1 = 1.25 atm, V1 = 2.35 L, and V2 = 3.50 L.
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Plug these values into the equation P1V1 = P2V2 and solve for P2 (the final pressure).
1.25 atm * 2.35 L = P2 * 3.50 L
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Divide both sides of the equation by 3.50 L to solve for P2:
P2 = (1.25 atm * 2.35 L) / 3.50 L
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Calculate the value to find P2:
P2 = 0.839 atm
So, the new pressure, if the volume is increased to 3.50 L, will be 0.839 atm. Therefore, the correct answer is 0.839 atm.
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