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If angle between two non-null vectors A""⃗ and B""⃗ is 130o and its resultant is C"⃗ thena. 0C"⃗ 0 must be equal to 0A""⃗ − B""⃗ 0b. 0C"⃗ 0 must be less than to 0A""⃗ − B""⃗ 0c. 0C"⃗ 0 must be greater than to 0A""⃗ − B""⃗ 0d. 0C"⃗ 0 may be equal to 0A""⃗ − B""⃗ 0

Question

If angle between two non-null vectors A""⃗ and B""⃗ is 130o and its resultant is C"⃗ thena. 0C"⃗ 0 must be equal to 0A""⃗ − B""⃗ 0b. 0C"⃗ 0 must be less than to 0A""⃗ − B""⃗ 0c. 0C"⃗ 0 must be greater than to 0A""⃗ − B""⃗ 0d. 0C"⃗ 0 may be equal to 0A""⃗ − B""⃗ 0

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Solution

The magnitude of the resultant vector C (denoted as ||C||) is given by the formula:

||C|| = sqrt(||A||^2 + ||B||^2 + 2*||A||*||B||*cos(θ))

where θ is the angle between vectors A and B, and ||A|| and ||B|| are the magnitudes of vectors A and B respectively.

The magnitude of the vector A - B (denoted as ||A - B||) is given by the formula:

||A - B|| = sqrt(||A||^2 + ||B||^2 - 2*||A||*||B||*cos(θ))

Comparing these two formulas, we can see that the only difference is the sign before the term 2*||A||||B||cos(θ). Since the angle between A and B is 130 degrees, which is more than 90 degrees, cos(θ) is negative. Therefore, the term 2||A||||B||*cos(θ) is negative in the formula for ||C|| and positive in the formula for ||A - B||.

This means that ||C|| must be less than ||A - B||. So, the correct answer is:

b. ||C|| must be less than ||A - B||.

This problem has been solved

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