Given a Binary Tree of size N, your task is to complete the function rightLeafSum(), which should return the sum of all the leaf nodes that are the right child of their parent of the given binary tree.
Question
Given a Binary Tree of size N, your task is to complete the function rightLeafSum(), which should return the sum of all the leaf nodes that are the right child of their parent of the given binary tree.
Solution
To solve this problem, you can use a recursive function that traverses the binary tree. Here is a step-by-step guide on how to do it:
-
Initialize a variable
sumto 0. This will hold the sum of all the right leaf nodes. -
Define a recursive function,
rightLeafSum(node), that takes a node of the binary tree as an argument. -
In the
rightLeafSum(node)function, check if the node is null. If it is, return 0 because a null node does not contribute to the sum. -
Check if the node has a right child and that right child is a leaf node (i.e., it does not have left or right children). If it is, add the value of the right child to
sum. -
Recursively call
rightLeafSum(node)for the left and right children of the current node. -
After the function has traversed the entire tree, return
sum.
Here is a Python code snippet that implements the above steps:
def rightLeafSum(node):
if node is None:
return 0
if node.right is not None and node.right.left is None and node.right.right is None:
return node.right.data + rightLeafSum(node.left)
return rightLeafSum(node.left) + rightLeafSum(node.right)
In this code, node.data is the value of the node, node.left is the left child of the node, and node.right is the right child of the node. The function rightLeafSum(node) returns the sum of all the right leaf nodes in the binary tree rooted at node.
Similar Questions
Given the root of a binary tree, return the sum of all left leaves.A leaf is a node with no children. A left leaf is a leaf that is the left child of another node.
Given the root of a binary tree and an integer targetSum, return true if the tree has a root-to-leaf path such that adding up all the values along the path equals targetSum.A leaf is a node with no children. Example 1:Input: root = [5,4,8,11,null,13,4,7,2,null,null,null,1], targetSum = 22Output: trueExplanation: The root-to-leaf path with the target sum is shown.Example 2:Input: root = [1,2,3], targetSum = 5Output: falseExplanation: There two root-to-leaf paths in the tree:(1 --> 2): The sum is 3.(1 --> 3): The sum is 4.There is no root-to-leaf path with sum = 5.Example 3:Input: root = [], targetSum = 0Output: falseExplanation: Since the tree is empty, there are no root-to-leaf paths. Constraints:The number of nodes in the tree is in the range [0, 5000].-1000 <= Node.val <= 1000-1000 <= targetSum <= 1000
whether all of its nodes have the value equal to the sum of their child nodes.
The function CountNumberOfNodes below is a recursive algorithm to find the totalnumber of nodes in the binary tree rooted at node x. Fill in the four blanks to make thisfunction work correctly.CountNumberOfNodes(Node x){If x≠NIL← CountNumberOfNodes(x.left)← CountNumberOfNodes(x.right)ReturnElseReturn}
Question7Max. score: 30.00Find the vertical sum in a given binary tree.You are given the root of a binary tree A.You have to find the vertical sum of the tree.A vertical sum denotes an array of sum of the different verticals of a binary tree,where the leftmost vertical sum is the first element of the array and rightmost vertical is the last.Sample input71 2 3 5 6 7 8Sample output9 6 11 6
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