The function CountNumberOfNodes below is a recursive algorithm to find the totalnumber of nodes in the binary tree rooted at node x. Fill in the four blanks to make thisfunction work correctly.CountNumberOfNodes(Node x){If x≠NIL← CountNumberOfNodes(x.left)← CountNumberOfNodes(x.right)ReturnElseReturn}
Question
The function CountNumberOfNodes below is a recursive algorithm to find the totalnumber of nodes in the binary tree rooted at node x. Fill in the four blanks to make thisfunction work correctly.CountNumberOfNodes(Node x){If x≠NIL← CountNumberOfNodes(x.left)← CountNumberOfNodes(x.right)ReturnElseReturn}
Solution
The function you're trying to complete is a recursive function to count the number of nodes in a binary tree. Here's how you can fill in the blanks:
def CountNumberOfNodes(Node x):
if x is not None:
left = CountNumberOfNodes(x.left)
right = CountNumberOfNodes(x.right)
return 1 + left + right
else:
return 0
This function works by checking if the current node x is None (or NIL). If it is, it returns 0 because there are no nodes in an empty tree. If x is not None, it recursively counts the number of nodes in the left and right subtrees, then adds 1 (for the current node) to these counts and returns the total.
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