Given a string S(input consisting) of ‘*’ and ‘#’. The length of the string is variable. The task is to find the minimum number of ‘*’ or ‘#’ to make it a valid string. The string is considered valid if the number of ‘*’ and ‘#’ are equal. The ‘*’ and ‘#’ can be at any position in the string.Note : The output will be a positive or negative integer based on number of ‘*’ and ‘#’ in the input string.(*>#): positive integer(#>*): negative integer(#=*): 0Example 1:Input 1:###*** -> Value of SOutput :0 ? number of * and # are equal
Question
Given a string S(input consisting) of ‘’ and ‘#’. The length of the string is variable. The task is to find the minimum number of ‘’ or ‘#’ to make it a valid string. The string is considered valid if the number of ‘’ and ‘#’ are equal. The ‘’ and ‘#’ can be at any position in the string.Note : The output will be a positive or negative integer based on number of ‘’ and ‘#’ in the input string.(>#): positive integer(#>): negative integer(#=): 0Example 1:Input 1:###*** -> Value of SOutput :0 ? number of * and # are equal
Solution
To solve this problem, you need to count the number of '*' and '#' in the string. Here are the steps:
- Initialize two counters, one for '*' and one for '#'.
- Iterate over the string. For each character, if it's a '', increment the '' counter. If it's a '#', increment the '#' counter.
- After the iteration, subtract the '#' counter from the '' counter. This will give you the difference between the number of '' and '#'. If the result is positive, it means there are more '' than '#'. If it's negative, there are more '#' than ''. If it's zero, the number of '*' and '#' are equal.
Here is a Python code snippet that implements these steps:
def min_chars(s):
star_count = s.count('*')
hash_count = s.count('#')
return star_count - hash_count
For example, if the input is '###**', the function will return 0, because the number of '' and '#' are equal.
Similar Questions
Given a string S(input consisting) of ‘*’ and ‘#’. The length of the string is variable. The task is to find the minimum number of ‘*’ or ‘#’ to make it a valid string. The string is considered valid if the number of ‘*’ and ‘#’ are equal. The ‘*’ and ‘#’ can be at any position in the string.Note : The output will be a positive or negative integer based on number of ‘*’ and ‘#’ in the input string.(*>#): positive integer(#>*): negative integer(#=*): 0Example 1:Input 1:###*** -> Value of SOutput :0 ? number of * and # are equal
10. Regular Expression MatchingAttemptedHardTopicsCompaniesGiven an input string s and a pattern p, implement regular expression matching with support for '.' and '*' where:'.' Matches any single character.'*' Matches zero or more of the preceding element.The matching should cover the entire input string (not partial). Example 1:Input: s = "aa", p = "a"Output: falseExplanation: "a" does not match the entire string "aa".Example 2:Input: s = "aa", p = "a*"Output: trueExplanation: '*' means zero or more of the preceding element, 'a'. Therefore, by repeating 'a' once, it becomes "aa".Example 3:Input: s = "ab", p = ".*"Output: trueExplanation: ".*" means "zero or more (*) of any character (.)".
Problem StatementBob loves playing a string-matching game where he tries to match two strings based on a specific pattern. In this game, players input two strings, and the game determines whether they match according to a set of rules. Here are the rules of the game:A '*' in the first string represents zero or more characters.A '?' in the first string represents exactly one character.Any other character in the first string must match the corresponding character in the second string.Bob has requested your assistance in completing the game mentioned above.Input format :The first line of input consists of a string str1 containing the characters along with the symbols - ? and *.The second line consists of the string str2, without any symbols.Output format :The first line displays the "Second string: " followed by str2 as string, representing the second input string.The second line displays the following format:"The strings match" if the first string matches the second according to the pattern rules."The strings do not match" if the first string does not match the second according to the pattern rules.Refer to the sample output for the formatting specifications.Code constraints :In the given scenario, the test cases fall under the following constraints:2 ≤ length of the string (str1, str2) ≤ 15Sample test cases :Input 1 :i?mneoiamneoOutput 1 :Second string: iamneoThe strings matchInput 2 :i?miaamOutput 2 :Second string: iaamThe strings do not matchInput 3 :i*mn?oiaamneoOutput 3 :Second string: iaamneoThe strings matchInput 4 :a?b?c?d?e?f?ghaxbxcydzefffghOutput 4 :Second string: axbxcydzefffghThe strings matchInput 5 :a*cacOutput 5 :Second string: acThe strings matchNote :The program will be evaluated only after the “Submit Code” is clicked.Extra spaces and new line characters in the program output will result in the failure of the test case.
Given an input string s, reverse the order of the words.A word is defined as a sequence of non-space characters. The words in s will be separated by at least one space.Return a string of the words in reverse order concatenated by a single space.Note that s may contain leading or trailing spaces or multiple spaces between two words. The returned string should only have a single space separating the words. Do not include any extra spaces. Example 1:Input: s = "the sky is blue"Output: "blue is sky the"Example 2:Input: s = " hello world "Output: "world hello"Explanation: Your reversed string should not contain leading or trailing spaces.Example 3:Input: s = "a good example"Output: "example good a"Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string. Constraints:1 <= s.length <= 104s contains English letters (upper-case and lower-case), digits, and spaces ' '.There is at least one word in s. Follow-up: If the string data type is mutable in your language, can you solve it in-place with O(1) extra space?
Find output of the below program:int main(){ char str[]={'e','a','r','t','h'}; printf("%s", str); return 0;}
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