Below is the DNA sequence for a short protein: 5’-ATG GCC ACT GAA TCC TGA ACG GAC GAA CGC ACA TCG-3’ How many amino acids will the protein be translated from the mRNA transcribed from the above sequence?12056

The DNA sequence provided is: 5’-ATG GCC ACT GAA TCC TGA ACG GAC GAA CGC ACA TCG-3’

First, we need to transcribe this DNA sequence into mRNA. The transcription process involves replacing Thymine (T) with Uracil (U). So, the mRNA sequence will be: 5'-AUG GCC ACU GAA UCC UGA ACG GAC GAA CGC ACA UCG-3'

Next, we translate the mRNA into a sequence of amino acids. Each set of three nucleotides, known as a codon, codes for one amino acid.

The mRNA sequence is: AUG GCC ACU GAA UCC UGA ACG GAC GAA CGC ACA UCG

This translates into the following amino acids:

AUG - Methionine (Met) GCC - Alanine (Ala) ACU - Threonine (Thr) GAA - Glutamic acid (Glu) UCC - Serine (Ser) UGA - Stop codon ACG - Threonine (Thr) GAC - Aspartic acid (Asp) GAA - Glutamic acid (Glu) CGC - Arginine (Arg) ACA - Threonine (Thr) UCG - Serine (Ser)

The stop codon (UGA) signals the end of the protein, so the amino acids after the stop codon are not translated into the protein.

So, the protein translated from the mRNA transcribed from the above sequence will be 5 amino acids long: Methionine - Alanine - Threonine - Glutamic acid - Serine.