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There is a very popular lottery in which a ticket is called a scratcher. In this lottery, 49% of the scratchers are winning ones. Suppose that we will take a random sample of 8 scratchers. Let p represent the proportion of winning scratchers from the sample. Consider the sampling distribution of the sample proportion p.Complete the following. Carry your intermediate computations to four or more decimal places. Write your answers with two decimal places, rounding if needed.(a)Find μp (the mean of the sampling distribution of the sample proportion).=μp (b)Find σp (the standard deviation of the sampling distribution of the sample proportion).=σp

Question

There is a very popular lottery in which a ticket is called a scratcher. In this lottery, 49% of the scratchers are winning ones. Suppose that we will take a random sample of 8 scratchers. Let p represent the proportion of winning scratchers from the sample. Consider the sampling distribution of the sample proportion p.Complete the following. Carry your intermediate computations to four or more decimal places. Write your answers with two decimal places, rounding if needed.(a)Find μp (the mean of the sampling distribution of the sample proportion).=μp (b)Find σp (the standard deviation of the sampling distribution of the sample proportion).=σp

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Solution

(a) The mean of the sampling distribution of the sample proportion (μp) is equal to the population proportion (P). In this case, P is given as 0.49 (49%). So, μp = P = 0.49.

(b) The standard deviation of the sampling distribution of the sample proportion (σp) can be calculated using the formula:

σp = sqrt [ P(1 - P) / n ]

where: P is the population proportion (0.49), n is the sample size (8).

Substituting the given values into the formula, we get:

σp = sqrt [ 0.49(1 - 0.49) / 8 ] σp = sqrt [ 0.2499 / 8 ] σp = sqrt [ 0.0312375 ] σp = 0.1767

So, the standard deviation of the sampling distribution of the sample proportion is approximately 0.18 (rounded to two decimal places).

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