How much heat is required to convert 25.0 g of liquid CCl4 from 0°C to 76.8°C. The specific heat of CCl4 is 0.866 J/g°C. Hint: Use q = mCΔT Group of answer choices1.66 kJ0.82 kJ1.22 kJ2.11 kJ
Question
How much heat is required to convert 25.0 g of liquid CCl4 from 0°C to 76.8°C. The specific heat of CCl4 is 0.866 J/g°C. Hint: Use q = mCΔT Group of answer choices1.66 kJ0.82 kJ1.22 kJ2.11 kJ
Solution
To solve this problem, we need to use the formula for heat transfer: q = mCΔT
Where:
- q is the heat transferred
- m is the mass of the substance
- C is the specific heat of the substance
- ΔT is the change in temperature
Given:
- m = 25.0 g
- C = 0.866 J/g°C
- ΔT = 76.8°C - 0°C = 76.8°C
Substitute these values into the formula:
q = (25.0 g)(0.866 J/g°C)(76.8°C)
q = 1661.04 J
Since the answer choices are given in kilojoules, we need to convert joules to kilojoules. There are 1000 joules in a kilojoule, so:
q = 1661.04 J * (1 kJ / 1000 J) = 1.66 kJ
So, the heat required to convert 25.0 g of liquid CCl4 from 0°C to 76.8°C is 1.66 kJ.
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