The molar mass of copper is 63.546 g/mol. The specific heat of copper is 0.385 How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C? a 973 J b 548 J c 8.63 J d 93.7 J
Question
The molar mass of copper is 63.546 g/mol. The specific heat of copper is 0.385 How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C?
a 973 J
b 548 J
c 8.63 J
d 93.7 J
Solution
To solve this problem, we need to use the formula for heat transfer:
q = mcΔT
where:
- q is the heat transferred,
- m is the mass,
- c is the specific heat, and
- ΔT is the change in temperature.
First, we need to find the mass of copper. We can do this by multiplying the number of moles by the molar mass:
m = 0.762 mol * 63.546 g/mol = 48.43 g
Next, we calculate the change in temperature:
ΔT = 52.2°C - 81.6°C = -29.4°C
We use a negative sign because the temperature is decreasing, which means heat is being released.
Finally, we can substitute these values into the formula to find the heat transferred:
q = (48.43 g)(0.385 J/g°C)(-29.4°C) = -548 J
So, the answer is (b) 548 J.
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