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The molar mass of copper is 63.546 g/mol. The specific heat of copper is 0.385 How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C? a 973 J b 548 J c 8.63 J d 93.7 J

Question

The molar mass of copper is 63.546 g/mol. The specific heat of copper is 0.385 How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C?

a 973 J

b 548 J

c 8.63 J

d 93.7 J

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Solution

To solve this problem, we need to use the formula for heat transfer:

q = mcΔT

where:

  • q is the heat transferred,
  • m is the mass,
  • c is the specific heat, and
  • ΔT is the change in temperature.

First, we need to find the mass of copper. We can do this by multiplying the number of moles by the molar mass:

m = 0.762 mol * 63.546 g/mol = 48.43 g

Next, we calculate the change in temperature:

ΔT = 52.2°C - 81.6°C = -29.4°C

We use a negative sign because the temperature is decreasing, which means heat is being released.

Finally, we can substitute these values into the formula to find the heat transferred:

q = (48.43 g)(0.385 J/g°C)(-29.4°C) = -548 J

So, the answer is (b) 548 J.

This problem has been solved

Similar Questions

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