Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ball’s journey will gravity be the greatest force acting on the ball?

Charlie throws a ball up into the air. While the ball is airborne, which is the greatest force acting on the ball to slow it down?

A student drops a ball from a height of  . The acceleration of the ball due to gravity is  .How long will it take the ball to reach the ground?

All are come togetherball is projected from the ground level in vertically upward direction with an initial velocity u. The ball goes up to a maximum height ( EMG ) and then starts moving downward. Finally the ball falls back on the ground. It is given that motion of the ball under the action of gravity alone( IFYS ) and effect of air resistance, if any, is negligible. What is the value of maximum height up to which the ball goes ? (ONT ) What time does the ball take to reach the highest point during its motion ?​​

Every word problem, there should be a conclusion. therefore add a conclusion to the following answer. "(a) The velocity of the ball at its highest point is 0 m/s. This is because at the highest point, the ball stops moving upwards and is about to start falling downwards. (b) The velocity of the ball 1 second before it reaches its highest point depends on the initial speed and the acceleration due to gravity. The acceleration due to gravity is approximately 9.8 m/s². So, if we denote the initial speed as v0, then the velocity 1 second before the highest point is v0 - 9.8 m/s. (c) The change in velocity during this 1-second interval is the final velocity minus the initial velocity, which is (v0 - 9.8 m/s) - v0 = -9.8 m/s. (d) The velocity of the ball 1 second after it reaches its highest point is -9.8 m/s. This is because the ball has started to fall and is accelerating downwards due to gravity. (e) The change in velocity during this 1-second interval is the final velocity minus the initial velocity, which is -9.8 m/s - 0 = -9.8 m/s. (f) The change in velocity during the 2-second interval is the final velocity after 2 seconds minus the initial velocity, which is (-9.8 m/s) - (v0 - 9.8 m/s) = -19.6 m/s. (g) The acceleration of the ball during any of these time intervals and at the moment the ball has zero velocity is -9.8 m/s². This is the acceleration due to gravity, and it is always acting on the ball, regardless of its velocity."

8Jeremy throws his ball up in the air, but the ball falls back to the ground. What force made the ball move without ever touching the ball? A. the air pressure pushing on the ball B. magnetism pulling on the ball C. Jeremy's hand pushing on the ball D. gravity pulling on the ball