Knowee
Questions
Features
Study Tools

Solve the matrix equation for $a,\ b,\ c,$a, b, c,​ and $d$d​ .$\begin{bmatrix}7&d\\5&b\end{bmatrix}=\begin{bmatrix}c&4\\a&17\end{bmatrix}$[7 d5 b]=[c 4a 17]​$a=$a=​ ,  $b=$b=​  ,  $c=$c=​  ,  $d=$d=​

Question

Solve the matrix equation for a, b, c,a,\ b,\ c,a, b, c,​ and ddd​ .[7d5b]=[c4a17]\begin{bmatrix}7&d\\5&b\end{bmatrix}=\begin{bmatrix}c&4\\a&17\end{bmatrix}[7 d5 b]=[c 4a 17]​a=a=a=​ ,  b=b=b=​  ,  c=c=c=​  ,  d=d=d=​

🧐 Not the exact question you are looking for?Go ask a question

Solution

The given matrix equation is:

[7d5b]=[c4a17]\begin{bmatrix}7&d\\5&b\end{bmatrix}=\begin{bmatrix}c&4\\a&17\end{bmatrix}

We can solve this equation by equating the corresponding elements in the two matrices.

From the first row and first column, we get:

7 = c

So, c = 7.

From the first row and second column, we get:

d = 4

So, d = 4.

From the second row and first column, we get:

5 = a

So, a = 5.

From the second row and second column, we get:

b = 17

So, b = 17.

Therefore, the solution to the matrix equation is a = 5, b = 17, c = 7, and d = 4.

This problem has been solved

Similar Questions

Solve the matrix equation for $a,\ b,\ c,$a, b, c,​ and $d$d​ .$\begin{bmatrix}7&d\\5&b\end{bmatrix}=\begin{bmatrix}c&4\\a&17\end{bmatrix}$[7 d5 b]=[c 4a 17]​$a=$a=​ ,  $b=$b=​  ,  $c=$c=​  ,  $d=$d=​

Solve the matrix equation for $a,\ b,\ c,$a, b, c,​ and $d$d​ .$-3\left(\begin{bmatrix}7&2b\\8c&8\end{bmatrix}-\begin{bmatrix}4&4b\\5&d\end{bmatrix}\right)=\begin{bmatrix}a&54\\63&d\end{bmatrix}$−3([7 2b8c 8]−[4 4b5 d])=[a 5463 d]​$a=$a=​ ,  $b=$b=​  ,  $c=$c=​  ,  $d=$d=​

Solve the matrix equation for $a,\ b,\ c,$a, b, c,​ and $d$d​ .$2\left(\begin{bmatrix}3a&11\\4&6\end{bmatrix}+\begin{bmatrix}-7&-6\\11&5d\end{bmatrix}\right)=\begin{bmatrix}22&b\\c&52\end{bmatrix}$2([3a 114 6]+[−7 −611 5d])=[22 bc 52]​$a=$a=​ ,  $b=$b=​  ,  $c=$c=​  ,  $d=$d=​

Solve the matrix equation for $a,\ b,\ c,$a, b, c,​ and $d$d​ .$\frac{1}{2}$12​​ $\begin{bmatrix}-6a&-2\\3&14\\-10&-8\end{bmatrix}+\begin{bmatrix}5&3\\-\frac{5}{2}&b-3\\6&-1\end{bmatrix}=\begin{bmatrix}9&4d\\-1&11\\c+4&-5\end{bmatrix}$[−6a −23 14−10 −8]+[5 3−52​ b−36 −1]=[9 4d−1 11c+4 −5]​$a=$a=​ ,  $b=$b=​  ,  $c=$c=​  ,  $d=$d=​  Skip to navigationPrevious25, Fully Attempted.26, Fully Attempted.27, Fully Attempted.28, Fully Attempted.29, Fully Attempted.30, Unattempted. Flagged31, Unattempted.32, Unattempted.33, Unattempted.34, Unattempted.Next

Solve the matrix equation for $a,\ b,\ c,$a, b, c,​ and $d$d​ .$\begin{bmatrix}a&b\\3&-4\end{bmatrix}=\begin{bmatrix}6&2\\c&d\end{bmatrix}$[a b3 −4]=[6 2c d]​$a=$a=​ ,  $b=$b=​  ,  $c=$c=​  ,  $d=$d=​

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.