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In the function f(n) = 3n - 7, what are the first 5 terms?Select one:a. 1, 2, 3, 4, 5b. 3, 5, 7, 9, 11c. -4, -1, 2, 5, 8d. -7, -5, -3, -1, 1

Question

In the function f(n) = 3n - 7, what are the first 5 terms?Select one:a. 1, 2, 3, 4, 5b. 3, 5, 7, 9, 11c. -4, -1, 2, 5, 8d. -7, -5, -3, -1, 1

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Solution

To find the first 5 terms of the function f(n) = 3n - 7, we substitute the first 5 natural numbers (1, 2, 3, 4, 5) into the function:

  1. For n = 1, f(1) = 3*1 - 7 = -4
  2. For n = 2, f(2) = 3*2 - 7 = -1
  3. For n = 3, f(3) = 3*3 - 7 = 2
  4. For n = 4, f(4) = 3*4 - 7 = 5
  5. For n = 5, f(5) = 3*5 - 7 = 8

So, the first 5 terms of the function f(n) = 3n - 7 are -4, -1, 2, 5, 8. Therefore, the correct answer is c. -4, -1, 2, 5, 8.

This problem has been solved

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