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Write the first six terms of the sequence, $f\left(n\right)=-n^3$f(n)=−n3​ .The first six terms of the sequence are , , , , , and .

Question

Write the first six terms of the sequence, f(n)=−n3f\left(n\right)=-n^3f(n)=−n3​ .The first six terms of the sequence are , , , , , and .

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Solution

Sure, let's find the first six terms of the sequence defined by the function f(n)=−n3f(n)=-n^3.

  1. For n=1n=1, f(1)=−13=−1f(1)=-1^3=-1.
  2. For n=2n=2, f(2)=−23=−8f(2)=-2^3=-8.
  3. For n=3n=3, f(3)=−33=−27f(3)=-3^3=-27.
  4. For n=4n=4, f(4)=−43=−64f(4)=-4^3=-64.
  5. For n=5n=5, f(5)=−53=−125f(5)=-5^3=-125.
  6. For n=6n=6, f(6)=−63=−216f(6)=-6^3=-216.

So, the first six terms of the sequence are -1, -8, -27, -64, -125, and -216.

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The sequence {(-1)n

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