A Flyback converter has the following specifications: input voltage Vin= 21 V, magnetising inductance Lm = 0.7 mH, output capacitance C= 267 uF, Switching Frequency Fsw=0.05 MHz, output resistance Ro= 4 Ohms, and output voltage Vo= 8 V, and N1/N2=4. Assume the converter is ideal. Calculate a) the duty cycle b) the average of the magnetising current c) the maximum of the magnetising current For cost reasons, we are asked to decrease the inductance of the converter you considered in the previous question by 30 times. The rest of the parameters of the converter such as input voltage, switching frequency, output load, capacitance, and transformer turn ratio are kept constant. If we use the same duty cycle that you calculated in part (a), what would be the output power of this new converter?

The Flyback converter is a type of switched-mode power supply that provides electrical isolation between the input and output and also provides multiple output voltages. It operates in discontinuous mode, meaning the current through the inductor (or the transformer primary) falls to zero before the next switching cycle begins.

a) The duty cycle (D) of a Flyback converter can be calculated using the formula:

D = Vo / (Vin * N2/N1)

Substituting the given values:

D = 8V / (21V * 1/4) = 0.152 or 15.2%

b) The average of the magnetising current (Im_avg) can be calculated using the formula:

Im_avg = D * Vo / (2 * Lm * Fsw)

Substituting the given values:

Im_avg = 0.152 * 8V / (2 * 0.7mH * 0.05MHz) = 1.737 A

c) The maximum of the magnetising current (Im_max) can be calculated using the formula:

Im_max = 2 * Im_avg = 2 * 1.737 A = 3.474 A

For the second part of the question, if the inductance is decreased by 30 times, the output power (Pout) of the converter can be calculated using the formula:

Pout = D^2 * Vin^2 / (2 * Lm * Fsw * Ro)

Substituting the given values and the new inductance (Lm_new = Lm / 30):

Pout = (0.152)^2 * (21V)^2 / (2 * 0.7mH/30 * 0.05MHz * 4 Ohms) = 0.457 W

So, the output power of the new converter would be approximately 0.457 W.