Determine the atmospheric pressure at a location where the barometric reading is 735 mmHg. Take the density of mercury to be 13,600 kg/m3. Express your answer in kPa.

Step 1: Convert the barometric reading from mmHg to meters of mercury (mHg) by dividing by 1000, since there are 1000 millimeters in a meter.

735 mmHg / 1000 = 0.735 mHg

Step 2: Use the formula for pressure in a fluid column to calculate the pressure in pascals (Pa). The formula is P = ρgh, where ρ is the density of the fluid (in this case, mercury), g is the acceleration due to gravity, and h is the height of the fluid column.

Take g to be 9.81 m/s² (the approximate value on the surface of the Earth).

P = (13,600 kg/m³) * (9.81 m/s²) * (0.735 m)

P = 98,500 Pa

Step 3: Convert the pressure from pascals to kilopascals (kPa) by dividing by 1000, since there are 1000 pascals in a kilopascal.

98,500 Pa / 1000 = 98.5 kPa

So, the atmospheric pressure at the location is approximately 98.5 kPa.