To solve this problem, we need to convert the pressure readings into the same units and then add them together to find the absolute pressure in the tank. Here are the steps:

1. Convert the manometer reading from mm of mercury to pascals (Pa). We know that 1 mm of mercury is equivalent to 133.322 Pa. So, 710 mm of mercury is equivalent to 710 * 133.322 = 94,658.42 Pa.

2. Convert the atmospheric pressure from kPa to Pa. We know that 1 kPa is equivalent to 1000 Pa. So, 101 kPa is equivalent to 101 * 1000 = 101,000 Pa.

3. Add the two pressures together to find the absolute pressure in the tank. So, 94,658.42 Pa + 101,000 Pa = 195,658.42 Pa.

Therefore, the absolute pressure in the nitrogen tank is 195,658.42 Pa.

Question

To solve this problem, we need to convert the pressure readings into the same units and then add them together to find the absolute pressure in the tank. Here are the steps:

1. Convert the manometer reading from mm of mercury to pascals (Pa). We know that 1 mm of mercury is equivalent to 133.322 Pa. So, 710 mm of mercury is equivalent to 710 * 133.322 = 94,658.42 Pa.

2. Convert the atmospheric pressure from kPa to Pa. We know that 1 kPa is equivalent to 1000 Pa. So, 101 kPa is equivalent to 101 * 1000 = 101,000 Pa.

3. Add the two pressures together to find the absolute pressure in the tank. So, 94,658.42 Pa + 101,000 Pa = 195,658.42 Pa.

Therefore, the absolute pressure in the nitrogen tank is 195,658.42 Pa.

Knowee AI · Accepted Answer

To solve this problem, we need to convert the pressure readings into the same units and then add them together to find the absolute pressure in the tank. Here are the steps:

1. Convert the manometer reading from mm of mercury to pascals (Pa). We know that 1 mm of mercury is equivalent to 133.322 Pa. So, 710 mm of mercury is equivalent to 710 * 133.322 = 94,658.42 Pa.

2. Convert the atmospheric pressure from kPa to Pa. We know that 1 kPa is equivalent to 1000 Pa. So, 101 kPa is equivalent to 101 * 1000 = 101,000 Pa.

3. Add the two pressures together to find the absolute pressure in the tank. So, 94,658.42 Pa + 101,000 Pa = 195,658.42 Pa.

Therefore, the absolute pressure in the nitrogen tank is 195,658.42 Pa.

A manometer attached to pressurized nitrogen tank reads 710 mm of mercury. If the atmospheric pressure is 101 kPa, what is the absolute pressure in the tank? The density of mercury is 13,600 kg/m3.

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