Use the following information to answer the question. The mean age of lead actresses from the top ten grossing movies of 2010 was 29.6 years with a standard deviation of 6.35 years. Assume the distribution of the actresses' ages is approximately unimodal and symmetric Between what two values would you expect to find about 68% of the lead actresses ages?
Question
Use the following information to answer the question. The mean age of lead actresses from the top ten grossing movies of 2010 was 29.6 years with a standard deviation of 6.35 years. Assume the distribution of the actresses' ages is approximately unimodal and symmetric Between what two values would you expect to find about 68% of the lead actresses ages?
Solution 1
To find the range of ages for about 68% of the lead actresses, we need to use the rule of 68-95-99.7. This rule states that for a normal distribution, about 68% of the data falls within one standard deviation of the mean.
Step 1: Calculate the lower limit of the range. Subtract the standard deviation from the mean: 29.6 - 6.35 = 23.25 years.
Step 2: Calculate the upper limit of the range. Add the standard deviation to the mean: 29.6 + 6.35 = 35.95 years.
So, we would expect about 68% of the lead actresses' ages to be between 23.25 and 35.95 years.
Solution 2
To find the range of ages for about 68% of the lead actresses, we can use the empirical rule (or 68-95-99.7 rule) which states that for a normal distribution, about 68% of the data falls within one standard deviation of the mean.
Step 1: Calculate the lower limit of the range. Subtract the standard deviation from the mean: 29.6 - 6.35 = 23.25 years.
Step 2: Calculate the upper limit of the range. Add the standard deviation to the mean: 29.6 + 6.35 = 35.95 years.
So, we would expect about 68% of the lead actresses' ages to be between 23.25 and 35.95 years.
Similar Questions
The ages of students at a university are normally distributed with a mean of 21. What percentage of the student age is at least 21 years old?Question 10Select one:a.21%b.1.96%c.50%d.It could be any value, depending on the magnitude of the standard deviation
The professior of a university believes that the average age of the bachelor students is 23. However, the tutor belives that the average age of the bachelor students differs from 23. To test the claim, they randomly selected 100 students, the average age was found to be 24.2 years. Assume the population standard deviation for the student age is 6 years. At the 1% level of significance, what is the test statistics?
A normal population has mean μ =33 and standard deviation σ =7.(a) What proportion of the population is between 18 and 29?
According to a Nielsen report, the average age of an audience watching American Idol Season 8 was 39.3 years with σ = 6 years. A random sample of 100 audiences for the Season 9 show yielded a mean age of 41.2 years. At the 5% significance level, do the data provide sufficient evidence to conclude that the population mean age of audience members for American Idol has increased? (hint: Conduct a Hypothesis Test)
A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year: 717 681 735 725 719 721 737 698 718 759 681 699 696716 719 722 733 720 690 691 768 709 736 761 687 Click here for the Excel Data FileRequired:a. Find the mean, median, and mode of this information. (Round the "Mean" to 2 decimal places.)b. What are the range and standard deviation? (Round the "Standard deviation" to 2 decimal places.)c. Use the Empirical Rule to establish an interval that includes about 95% of the observations. (Round your answers to 2 decimal places.) PrevQuestion 10 of 15 Total10 of 15Visit question mapNext
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.