A projectile is shot vertically upward with some initial velocity.It reaches a maximum height of 100 m.If, on a second shot, the initial velocity is doubled, what will the new maximum height be?Neglect friction and express your answer in meters.
Question
A projectile is shot vertically upward with some initial velocity.It reaches a maximum height of 100 m.If, on a second shot, the initial velocity is doubled, what will the new maximum height be?Neglect friction and express your answer in meters.
Solution
The maximum height (h) a projectile reaches when shot vertically upward is given by the equation h = (v^2) / (2g), where v is the initial velocity and g is the acceleration due to gravity.
In the first scenario, the maximum height reached is 100 m. So, we have 100 = (v^2) / (2g).
In the second scenario, the initial velocity is doubled. So, the new maximum height (h') is given by h' = ((2v)^2) / (2g) = 4 * (v^2) / (2g) = 4 * 100 = 400 m.
So, if the initial velocity is doubled, the new maximum height will be 400 meters.
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