An athlete loses 1.8 kg of water from her body through sweating during a training session that lasts one hour.Estimate the rate of energy loss by the athlete due to sweating. The specific latent heat of evaporation of water is 2.3×106 J kg–1.
Question
An athlete loses 1.8 kg of water from her body through sweating during a training session that lasts one hour.Estimate the rate of energy loss by the athlete due to sweating. The specific latent heat of evaporation of water is 2.3×106 J kg–1.
Solution
The rate of energy loss can be calculated using the formula:
Energy = mass * specific latent heat
Given: Mass (m) = 1.8 kg Specific latent heat (L) = 2.3×10^6 J kg–1
Substituting the given values into the formula:
Energy = 1.8 kg * 2.3×10^6 J kg–1 = 4.14×10^6 J
This is the total energy lost in one hour. To find the rate of energy loss per second (since the rate is usually measured in Watts, which is Joules per second), we need to divide this by the number of seconds in an hour (3600 seconds):
Rate of energy loss = 4.14×10^6 J / 3600 s = 1150 W
So, the athlete is losing energy at a rate of approximately 1150 Watts due to sweating.
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