A glass containing 50 g of water is left on a table in a room. After some time, only 10 g of the water remained. The specific latent heat of vaporization of water is 2.3 x 106 J kg-1. Determine the energy lost by the water in the glass due to evaporation.
Question
A glass containing 50 g of water is left on a table in a room. After some time, only 10 g of the water remained. The specific latent heat of vaporization of water is 2.3 x 106 J kg-1. Determine the energy lost by the water in the glass due to evaporation.
Solution
Sure, here are the steps to solve this problem:
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First, we need to find out how much water has evaporated. We do this by subtracting the final amount of water from the initial amount. So, 50g - 10g = 40g of water has evaporated.
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Next, we need to convert this mass from grams to kilograms, since the specific latent heat is given in J/kg. We know that 1kg = 1000g, so 40g = 0.04kg.
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Now we can calculate the energy lost due to evaporation. The formula for this is Q = mL, where Q is the energy, m is the mass, and L is the specific latent heat. Substituting the given values, we get Q = 0.04kg * 2.3 x 10^6 J/kg.
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Doing the multiplication, we find that Q = 92,000 J.
So, the water in the glass lost 92,000 Joules of energy due to evaporation.
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