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Calculate the number of ethanol molecules in 15.20g of ethanol (CH3CH2OH).

Question

Calculate the number of ethanol molecules in 15.20g of ethanol (CH3CH2OH).

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Solution

Sure, here are the steps to calculate the number of ethanol molecules in 15.20g of ethanol (CH3CH2OH):

Step 1: Calculate the molar mass of ethanol (CH3CH2OH). The molar mass of carbon (C) is approximately 12.01 g/mol, hydrogen (H) is approximately 1.01 g/mol, and oxygen (O) is approximately 16.00 g/mol.

Ethanol has 2 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom. So, the molar mass of ethanol is (212.01 g/mol) + (61.01 g/mol) + (16.00 g/mol) = 46.07 g/mol.

Step 2: Use the molar mass to convert grams of ethanol to moles of ethanol. The number of moles is equal to the mass of the substance divided by its molar mass. So, 15.20g ÷ 46.07 g/mol = 0.33 moles of ethanol.

Step 3: Use Avogadro's number to convert moles of ethanol to molecules of ethanol. Avogadro's number, which is 6.022 x 10^23 molecules/mol, is the number of molecules in one mole. So, 0.33 moles * 6.022 x 10^23 molecules/mol = 1.987 x 10^23 molecules of ethanol.

So, there are approximately 1.987 x 10^23 molecules of ethanol in 15.20g of ethanol.

This problem has been solved

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