Two bodies of masses m1 and m2 have same kinetic energy. The ratio of their momentum is
Question
Two bodies of masses m1 and m2 have same kinetic energy. The ratio of their momentum is
Solution
The kinetic energy (K.E) of a body is given by the formula K.E = 1/2 mv^2, where m is the mass and v is the velocity of the body.
Given that the two bodies have the same kinetic energy, we can write:
1/2 m1v1^2 = 1/2 m2v2^2
This simplifies to:
m1v1^2 = m2v2^2
Taking the square root of both sides to solve for the velocities, we get:
v1 = sqrt(m2/m1) * v2
The momentum (p) of a body is given by the formula p = mv. Substituting the velocities we found into this formula, we get:
p1 = m1 * sqrt(m2/m1) * v2 = sqrt(m1*m2) * v2 p2 = m2 * v2
Therefore, the ratio of their momenta (p1/p2) is:
p1/p2 = sqrt(m1*m2) * v2 / (m2 * v2) = sqrt(m1/m2)
So, the ratio of their momenta is the square root of the ratio of their masses.
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