A works twice as fast as B. If both of them can together finish a task in 12 days, B alone can do it in:
Question
A works twice as fast as B. If both of them can together finish a task in 12 days, B alone can do it in:
Solution
Sure, let's solve this step by step:
Step 1: Let's assume the amount of work to be 1 (for simplicity).
Step 2: Let's denote the work done by B in one day as 'b'. Since A works twice as fast as B, the work done by A in one day would be '2b'.
Step 3: According to the problem, A and B together can finish the work in 12 days. So, the total work done by A and B in one day would be 1/12.
Step 4: We can set up the equation as follows: b (work done by B in one day) + 2b (work done by A in one day) = 1/12.
Step 5: Simplifying the equation gives 3b = 1/12. Solving for 'b', we get b = 1/36. This means B can finish the work in 36 days when working alone.
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