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Aptitude:speed and distance [Section 1 of 1] Q18 of 30 Marks 1 General Instructions 100% ×CloseTest time left: 10:10Select the correct answerTwo cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach their common destination at the same point of time. If the first car travelled for at least 6 hours, then the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is?

Question

Aptitude:speed and distance [Section 1 of 1] Q18 of 30 Marks 1 General Instructions 100% ×CloseTest time left: 10:10Select the correct answerTwo cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach their common destination at the same point of time. If the first car travelled for at least 6 hours, then the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is?

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Solution

The problem is asking for the highest possible percentage increase in speed of the second car compared to the first car.

Here's how to solve it:

  1. Let's assume the distance both cars need to travel is D (it doesn't matter what the actual distance is, as it's the same for both cars).

  2. The first car starts at 10:00 am and travels for at least 6 hours, so it arrives at the destination at 4:00 pm at the earliest.

  3. The second car starts at 11:00 am and arrives at the same time as the first car, so it travels for at most 5 hours.

  4. The speed of a car is given by the distance it travels divided by the time it takes. So, the speed of the first car is D/6 and the speed of the second car is D/5.

  5. To find the percentage increase in the speed of the second car compared to the first, we subtract the speed of the first car from the speed of the second car, divide by the speed of the first car, and then multiply by 100.

Doing this calculation gives us ((D/5 - D/6) / (D/6)) * 100 = 20%.

So, the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is 20%.

This problem has been solved

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